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Posted on 11/10/20 at 10:01 am to Chicken
I can do this. Saving this spot to post my work.
Posted on 11/10/20 at 10:02 am to Chicken
-2
Posted on 11/10/20 at 10:02 am to BayouBengal23
quote:
Probably -2 or something in that ball park
Correct... but I don't really remember how to solve that algebraically.
Posted on 11/10/20 at 10:02 am to Chicken
quote:
If triangle COA has coordinates C(10,1), A(3, -4) and O (d, 3), determine the value of d so that the triangle is a right triangle with hypotenuse OC. Show algebraic work.
You know that a^2 + b^2 = c^2.
if segment OC is the hypotneuse of a right triangle, that means that the other 2 legs are perpendicular to each other. Graph it out and figure out the length of segments AC and AO using the (x,y) coordinates. Make those the a & b sides, square them, add together. then take the square root and you have the value for d.
Posted on 11/10/20 at 10:02 am to Chicken
Plot out A and C. The inverse of that slope is what the slope from A to O should be so that it is a right angle. (inverse may be the incorrect term but you know what I mean, that slope should be perpendicular to the slope of A C).
instead of rise over run of A to C, make it as the run over rise - so it should be like the negative inverse of their slope.
ETA: I got it first! Give me a year of free TD premium please.
instead of rise over run of A to C, make it as the run over rise - so it should be like the negative inverse of their slope.
ETA: I got it first! Give me a year of free TD premium please.
This post was edited on 11/10/20 at 10:24 am
Posted on 11/10/20 at 10:03 am to Chicken
quote:
determine the value of d
D=350
Posted on 11/10/20 at 10:03 am to Chicken
d = -2
you want the slope of AO to be the negative inverse of AC. slope of AC = 5/7 so the slope of AO needs to be -7/5
you want the slope of AO to be the negative inverse of AC. slope of AC = 5/7 so the slope of AO needs to be -7/5
Posted on 11/10/20 at 10:04 am to Chicken
Do your own homework, washout
Posted on 11/10/20 at 10:04 am to Chicken
350
This post was edited on 11/10/20 at 10:07 am
Posted on 11/10/20 at 10:04 am to Chicken
Is this a Billy Madison situation?
Posted on 11/10/20 at 10:06 am to Chicken
i need that graphing paper with the squares
Posted on 11/10/20 at 10:11 am to VinegarStrokes
quote:
d = -2
you want the slope of AO to be the negative inverse of AC. slope of AC = 5/7 so the slope of AO needs to be -7/5
This is correct. The negative inverse slope gives you a right angle.
y=-(7/5)x+b
Plug in your coordinates for point A to solve for b
-4=(-7/5)(3)+b
b=1/5
Then plug in your coordinates for O:
3=(-7/5)x+(1/5)
x=-2
Posted on 11/10/20 at 10:15 am to Ingeniero
Posted on 11/10/20 at 10:15 am to Chicken
I'm a geometry teacher so I'll help you out.
If the hypotenuse is OC then CA and AO must be perpendicular to each other to make that right angle.
Since we don't know what the exact point for O is we can get the slope of CA using the slope formula (y2-y1)/(x2-x1). Plugging in numbers we get (1--4)/(10-3) which = 5/7 for the slope of CA.
The perpendicular slope has to be the opposite +- sight and the reciprocal, so -7/5.
Now I can plug AO into the slope formula and set it equal to -7/5. With numbers plugged in it looks like (3--4)/(d-3)=-7/5. Simplified it would be 7/(d-3)=-7/5. Cross multiply to get -7(d-3)=35.
Distribute: -7d+21=35.
Subtract 21 from both sides: -7d=14.
Divide: d=-2
If the hypotenuse is OC then CA and AO must be perpendicular to each other to make that right angle.
Since we don't know what the exact point for O is we can get the slope of CA using the slope formula (y2-y1)/(x2-x1). Plugging in numbers we get (1--4)/(10-3) which = 5/7 for the slope of CA.
The perpendicular slope has to be the opposite +- sight and the reciprocal, so -7/5.
Now I can plug AO into the slope formula and set it equal to -7/5. With numbers plugged in it looks like (3--4)/(d-3)=-7/5. Simplified it would be 7/(d-3)=-7/5. Cross multiply to get -7(d-3)=35.
Distribute: -7d+21=35.
Subtract 21 from both sides: -7d=14.
Divide: d=-2
This post was edited on 11/10/20 at 10:18 am
Posted on 11/10/20 at 10:16 am to Chicken
Make a line perpendicular to C-A, then find where it intercepts the y=3
Posted on 11/10/20 at 10:16 am to VinegarStrokes
quote:got it...this helps...
d = -2
you want the slope of AO to be the negative inverse of AC. slope of AC = 5/7 so the slope of AO needs to be -7/5
Posted on 11/10/20 at 10:16 am to Chicken
(no message)
This post was edited on 2/4/25 at 8:58 am
Posted on 11/10/20 at 10:17 am to Chicken
nerds
Posted on 11/10/20 at 10:17 am to gar90
quote:
I'm a geometry teacher
Whore
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